contestada

Question
The value of a computer y, depreciates, or decreases as time passes. A computer was purchased for $3200 in 2018. In
2020 the computer was worth $2000. Assume the relationship between number of years after 2018 x, and value of
computer, y is linear.

Question The value of a computer y depreciates or decreases as time passes A computer was purchased for 3200 in 2018 In 2020 the computer was worth 2000 Assume class=

Respuesta :

raphealnwobi

The value of the computer decreases by $800 per year.

A linear equation is given by:

y = mx + b

where y, x are variables, m is the rate of change, b is the initial vale of y (y intercept).

Let y represent the cost of the computer and x represent the years after 2018.

A computer was purchased for $3200 in 2018. It is represented by the point (0, 3200). Also, in  2020 the computer was worth $2000, it is represented by the point (2, 2000). Hence:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-3200=\frac{2000-3200}{2-0}(x-0)\\\\y-3200=-800x\\\\y=-800x+3200[/tex]

Therefore the value of the computer decreases by $800 per year.

Find out more at: https://brainly.com/question/13911928

MrRoyal

A linear relationship will always decrease or increase at a constant and uniform rate.

  • The linear equation is [tex]\mathbf{y = -600x +3200}[/tex]
  • The estimated value in 2022 is $800
  • The estimated value in 2024 is -$400, and it does not make sense

Part 1

(a) The linear equation

In 2018, the value is $3200

In 2020, the value is $2000

Let the number of years since 2018 be x, and the value be y

So, we have the following representation

[tex]\mathbf{(x,y) = (0,3200) (2,2000)}[/tex]

Start by calculating the slope (m)

[tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex]

So, we have:

[tex]\mathbf{m = \frac{2000 - 3200}{2 - 0}}[/tex]

[tex]\mathbf{m = \frac{- 1200}{2}}[/tex]

Divide

[tex]\mathbf{m = - 600}[/tex]

The equation is then calculated as:

[tex]\mathbf{y = m(x -x_1) +y_1}[/tex]

So, we have:

[tex]\mathbf{y = -600(x -0) +3200}[/tex]

[tex]\mathbf{y = -600x +3200}[/tex]

Hence, the linear equation is [tex]\mathbf{y = -600x +3200}[/tex]

(b) The estimated value in 2022

In 2022, x = 4

So, we substitute 4 for x in the linear equation

[tex]\mathbf{y = -600x +3200}[/tex]

[tex]\mathbf{y = -600 \times 4 +3200}[/tex]

[tex]\mathbf{y = 800}[/tex]

Hence, the value in 2022 is $800

Part 2

The estimated value in 2024

In 2024, x = 6

So, we substitute 6 for x in the linear equation

[tex]\mathbf{y = -600x +3200}[/tex]

[tex]\mathbf{y = -600 \times 6 +3200}[/tex]

[tex]\mathbf{y = -400}[/tex]

Hence, the value in 2024 is -$400

This value does not make sense, because the value cannot be negative

Read more about linear equations at:

https://brainly.com/question/14323743

Otras preguntas