First, we need to split this into two problems. One problem where the absolute value is positive, and one where the absolute value is negative.
1. +(3X-4)=15
2. -(3X-4)=15
Now we need to solve. Let's solve "1" first
3X-4=15
First, we need to get 3X by itself. We do this by adding four to both sides.
3X-4+4=15+4
3X=19
Now we divide both sides by 3.
3X/3=19/3
X=19/3
Now we have one of our answers. However, all of the choices have 19/3 as part of the answer, so we cannot eliminate any choices.
Next we solve our second problem.
-(3X-4)=15
We must first get rid of the parentheses. Because the negative sign distributes, we must change the signs of 3X and -4.
-(3X-4)=15
-3X+4=15
Now we need to get -3X by itself. We do this by subtracting 4 from both sides.
-3X+4-4=15-4
-3X=11
Now we need to divide both sides by -3.
(-3X)/(-3)=11/(-3)
X=11/(-3)
The negative sign on the bottom affects the whole right side, so we can move the negative to the front.
X=11/(-3)
X=-11/3
Now that we have the second answer, we can say that the answer is "c."
