The voltage of the secondary will be 36 V.From the given conditions primary transformer has 3 times as many turns in the secondary coil.
Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.
Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.
The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.
Given data;
Primary coil voltage,[tex]\rm V_P = 12 \ v[/tex]
Secondary coil voltage,[tex]\rm V_s = ?[/tex]
No turns in the primary coil,[tex]\rm N_p[/tex]
No turns in the secondary coil,[tex]\rm N_s[/tex]
From the given condition;
[tex]\rm N_s = 3N_p[/tex]
For a transformer,
[tex]\rm \frac{V_p}{V_s}= \frac{N_p}{N_s} \\\\ \rm \frac{12}{V_s}= \frac{N_p.}{3N_p} \\\\ V_s = 36 \ V[/tex]
Hence the voltage of the secondary will be 36 V.
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