The question is missing a tabular data. So, it is attached below.
Answer:
The total cost for the party is $74.50.
Step-by-step explanation:
Given:
Lanes rented at regular cost = 4
Cost of 1 lane rented at regular cost = $9.75
Cost of 1 lane rented for members = $7.50
Cost of 1 shoe rental at regular cost(non members) = $3.95
Cost of 1 shoe rental for members = $2.95
Since, lanes are rented at regular cost, we use unit rate at regular cost
So, cost of 4 lanes rented = [tex]4\times 9.75= \$ 39[/tex]
Now, out of 10 people who rented shoes, 4 are members. So, the number of non-members is given as:
Non members who rented shoes = 10 - 4 = 6
So, 4 members and 6 nonmembers rented shoes.
So, cost of 6 non members renting shoes = [tex]6\times 3.95=\$ 23.70[/tex]
Cost of 4 members renting shoes = [tex]4\times 2.95=\$ 11.80[/tex]
Total cost for the party is the sum of all the costs. This gives,
= 39 + 11.80 + 23.70
= 50.80 + 23.70
= $74.50
Therefore, the total cost for the party is $74.50.
