The only important thing to note of the given problem is the molecular formula, PbSO₄. From its form, we know it is an ionic compound because it consists of a cation in the form of Lead (Pb) and anion in the form of sulfate (SO₄). The charge for sulfate is -2. The charge for Pb could be +1, +2,or +3. Since the compound does not have any subscript, that means they have cancelled out. So, that means that the charge of Pb is +2 to cancel out with sulfate's -2. Thus, the answer is B.