Respuesta :
using Pythagoras theorem
let the hypotenuse be h
[tex] {h}^{2} = {12}^{2} + {16}^{2} \\ {h}^{2} = 144 + 256 \\ {h}^{2} = 400 \\ h = \sqrt{400} \\ h = 20cm[/tex]
the answer is D
pls mark me as brainliest
let the hypotenuse be h
[tex] {h}^{2} = {12}^{2} + {16}^{2} \\ {h}^{2} = 144 + 256 \\ {h}^{2} = 400 \\ h = \sqrt{400} \\ h = 20cm[/tex]
the answer is D
pls mark me as brainliest
Answer:
D.20 cm
Step-by-step explanation:
Hello there
I think I can help you with this,you can solve this by using the Pythagoras theorem,which establishes
[tex]side^{2}+side^{2}=hypotenuse^{2}[/tex]
step 1
isolate hypotenuse from the equation
[tex]side^{2}+side^{2}=hypotenuse^{2}\\\sqrt{side^{2}+side^{2}} =hypotenuse[/tex]
we will take only the positive root, because we are finding a distance
Step 2
replace
Let
side=12 cm
side=16 cm
[tex]hypotenuse=\sqrt{side^{2}+side^{2}} \\hypotenuse=\sqrt{(12\ cm)^{2}+(16\ cm)^{2}}\\hypotenuse=\sqrt{144\ cm^{2}+256\ cm^{2}}\\hypotenuse=\sqrt{400\ cm^{2}}\\hypotenuse=20\ cm\\\\[/tex]
D.20 cm
Have a nice day.