Respuesta :
we are given
62% of the students take math
so,
[tex]n(M)=62[/tex]
49% take science
[tex]n(S)=49[/tex]
38% take both science and math
n(M∩S)=38
now, we can use union formula
n(M∪S)=n(M)+n(S) -n(M∩S)
now, we can plug values
and we get
n(M∪S)=62+49 -38
n(M∪S)=73
so,
the percentage takes at least one science or math course is 73%..........Answer
P(M)=0.62,P(S)=0.49,P(S and M)=0.39
From the above
P(m)=0.62,p(s)=0.49,p(s and m)=0.38
The percentage of students that takes at least one science or math
P(s and m)=p(s)+p(m)-p(s and m)
=0.49+0.62-0.38
=73
