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Mark estimates that the distance from his house to his school is 15.5 mi. The actual distance is 14.5 mi. To the nearest tenth of a percent, what is the percent error in Mark's estimate?

Respuesta :

altavistard
The error is 1.0 mile, too large.

Write the ratio 

1.0 mile
--------------- = 0.069
14.5 miles

Mark's estimate is 6.9% greater than the actual distance.

MrRoyal

The percentage error of the estimate is 6.9%

How to calculate the percentage error

The data values are given as:

Actual = 14.5 miles

Estimate = 15.5 miles

The percentage error in the estimate is then calculated as:

[tex]\%Error = \frac{E - A}{A} *100\%[/tex]

So, we have:

[tex]\%Error = \frac{15.5 - 14.5}{14.5} *100\%[/tex]

Evaluate

[tex]\%Error = 6.9\%[/tex]

Hence, the percentage error of the estimate is 6.9%

Read more about percentage error at:

https://brainly.com/question/5493941

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