Respuesta :

[tex] \frac{11(9^2-5^2)}{2^2+8} = \frac{11(81-25)}{4+8} = \frac{11*56}{12} = \frac{11*28}{6} = \frac{11*14}{3} = \frac{154}{3} [/tex]= 51.333333333 ≈ 51.3

Hence, the answer is C.
david8644

Answer:

51.3

Step-by-step explanation:

In order to calculate this, you have to remember the norms for the solution of math problems with hierarchy of operations called PEMDAS:

   Parentheses (simplify inside 'em)

   Exponents

   Multiplication and Division (from left to right)

   Addition and Subtraction (from left to right)

So we first solve parentheses:

11[(9^2-5^2)= 11(81-25)=11(56)= 616.

and now we have to divide that by the result of:

2^2+8

Remember first exponents:

2^2+8= 4+8=12

ANd now we just divide:

616/12=51.3333

So the answer would be 51.3

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