Myarose99
contestada

If 5.40 kcal of heat is added to 1.00 kg of water at 100⁰C, how much steam at 100⁰C is produced? Show all calculations leading to an answer.

Respuesta :

mathmate
Heat of vaporization of water = 540 cal/g
m=1000 g
energy supplied = 5.4 kcal=5400 cal
T1=T2=100 deg. C
so all energy is used to convert to steam
mass of steam produced = 5400 cal /(540 cal/g)
=5400/540 cal *g/cal
=10 g

A kind of transformation known as phase change, in this when one is performing phase change, the component remains at the similar temperature all through the phase change. This is illustrated as whether one is heating or cooling the substance down. The heat subtracted or added relies upon the mass of the substance or the Latent Heat of the substance.  

The heat added or subtracted is given by the formula:  

Q = mL

Q is heat, L is latent heat of vaporization, which is 539 kcal/kg, and m is the mass of steam

m = Q/L = 5.4/539 = 0.01 Kg

m = 10 grams of steam.