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BlueSky06
The amount of heat, H, needed to boil off certain mass, m, of the substance is given by the equation,
                                H = mHv
where Hv is the heat of vaporization. Manipulating the equation, the mass is calculated by,
                                m = H/Hv
Substituting the known values,
                                m = 15000 J/(850 J/g) = 17.65 g
Thus, the mass of ethyl alcohol is approximately 17.65 g. 

Answer:

17.64 grams of ethyl alcohol can be boiled using 15000 J of energy.

Explanation:

Heat of vaporization of ethyl alcohol = [tex]=\Delta H_{vap}850 J/g[/tex]

Mass of ethyl alcohol boiled using 15000 Joule of energy = m

Q = 15000 J

[tex]Q=m\times \Delta H_{vap}[/tex]

[tex]15000 J=m\times 850 J/g[/tex]

m = 17.64 g

17.64 grams of ethyl alcohol can be boiled using 15000 J of energy.

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