Respuesta :
you add exponents when multiplied so
(2)^2*x^2+y^2+5
4x^2+y^7
four x to the second power plus y to the 7th power
(2)^2*x^2+y^2+5
4x^2+y^7
four x to the second power plus y to the 7th power
Answer:
40x^2y^6
Step-by-step explanation:
Expand the binomial (2x + y^2)^5
WE need to find the fourth term in the expansion
USe pascals triangle to find the coefficients
1 5 10 10 5 1
[tex](2x + y^2)^5= 1(2x)^5(y^2)^0 + 5(2x)^4(y^2)^1+10(2x)^3(y^2)^2+10(2x)^2(y^2)^3+ 5(2x)^1(y^2)^4+1(2x)^0(y^2)^1[/tex]
[tex]32x^5+80x^4y^2+80x^3y^4+40x^2y^6+10xy^8+y^{10}[/tex]
Fourth term in the expansion is
[tex]40x^2y^6[/tex]