Respuesta :
the minimum mass of sulfuric acid that could be left over by the chemical reaction is 0.4608 mol.
How to calculate ?
H2SO4(aq) + 2NaOH(s) ==> Na2SO4(aq) + 2H2O(l) ... balanced equation
Find the reactant that is the limit. Determine which is less by dividing the moles of each reactant by the corresponding coefficient in the balanced equation.
For H2SO4: 45.1 g H2SO4 x 1 mol H2SO4/98 g = 0.4602 mols (÷1>0.4602)
For NaOH: 47. g NaOH x 1 mol NaOH / 40. g = 1.175 mols (÷2->1.175)
Since 0.4602 is less than 1.175, H2SO4 is our limiting reactant, and the greatest amount of product that may be created will depend on the moles of H2SO4.
If the reaction is allowed to finish, there can be no more H2SO4 than a minimum mass of 0 grams. There shouldn't be any NaOH left over because it will run out before it is completely consumed.
That's a different matter if you meant to inquire about the smallest mass of NaOH that might possibly remain. In that scenario, you'll need to submit the problem again.
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