The distance covered by the car before it stops is 98.58 m.
Force acting on the car will be
ma = -mg sinθ
where,
m = mass of the car
a = acceleration of the car
g = acceleration due to gravity
θ = angle of inclination
Given,
θ = 10°
Put the values in the above equation,
ma = -mg sinθ
a = -g sin 10°
a = -10 (0.173)
a = -1.73 m/s²
We know the initial velocity is 18.2m/s and when the car comes to a stop the final velocity becomes zero.
u = 18.2 m/s
v= 0 m/s
Using one of the kinematics equations,
v² - u² = 2as
0 - (18.2)² = 2 (-1.73) (s)
331.24 = 3.36 (s)
s = 98.58 m
Hence, the distance covered by the car before it stops is 98.58 m.
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