Respuesta :
Answer with explanation:
Size of the sample = n =225
Mean[\text] \mu[/text]=48.5
Standard deviation [\text] \sigma[/text]= 1.8
[tex]Z_{90 \text{Percent}}=Z_{0.09}=0.5359\\\\Z_{score}=\frac{\Bar X -\mu}{\frac{\sigma}{\sqrt{\text{Sample size}}}}\\\\0.5359=\frac{\Bar X -48.5}{\frac{1.8}{\sqrt{225}}}\\\\0.5359=15 \times \frac{\Bar X -48.5}{1.8}\\\\0.5359 \times 1.8=15 \times (\Bar X -48.5)\\\\0.97=15 \Bar X-727.5\\\\727.5+0.97=15 \Bar X\\\\728.47=15 \Bar X\\\\ \Bar X=\frac{728.47}{15}\\\\\Bar X=48.57[/tex]
→Given Confidence Interval of Mean =48.8
→Calculated Mean of Sample =48.57 < 48.8
So, the value of Sample mean lies within the confidence interval.
Answer:
sample answer
Step-by-step explanation:
To find the margin of error, multiply the z-score by the standard deviation, then divide by the square root of the sample size.
The z*-score for a 90% confidence level is 1.645.
The margin of error is 0.20.
The confidence interval is 48.3 to 48.7.
48.8 is not within the confidence interval.
