Answer:
0.141 M
Explanation:
Step 1: Write the balanced neutralization reaction
H₂SO₄ + 2 NaOH ⇒ Na₂SO₄ + 2 H₂O
Step 2: Calculate the reacting moles of NaOH
17.45 mL of 0.425 M NaOH react.
0.01745 L × 0.425 mol/L = 7.42 × 10⁻³ mol
Step 3: Calculate the moles of H₂SO₄ that reacted with 7.42 × 10⁻³ moles of NaOH
The molar ratio of H₂SO₄ to NaOH is 1:2. The reacting moles of H₂SO₄ are 1/2 × 7.42 × 10⁻³ mol = 3.71 × 10⁻³ mol.
Step 4: Calculate the molarity of H₂SO₄
3.71 × 10⁻³ moles of H₂SO₄ are in 26.30 mL of solution.
[H₂SO₄] = 3.71 × 10⁻³ mol/26.30 × 10⁻³ L = 0.141 M
