Answer:
The 41st term of the given series is 324
Step-by-step explanation:
a= 4
a2= 12
d= a2-a
d= 12-4 = 8
now, we have to find 41 term that is a41
a41 = a+ 40d
a41= 4+ 40× 8
a41= 4+ 320
= 324
therefore the 41st term is 324
Answer:
324
Step-by-step explanation:
The sequence observed appears to be an arithmetic sequence. The formula for an arithmetic sequence is an = a1 + (n - 1)d, where an is the nth term, a1 is the first term, n is the term position, and d is the common difference. Let's write down what we know.
n = 41
a1 = 4
d = 8
So, let's plug our values into the equation and solve.
an = 4 + (41 - 1)8
an = 4 + (40)8
an = 4 + 320
an = 324
