Respuesta :

chemistryfan63

Answer:

see below

Step-by-step explanation:

I'm assuming you want to find the roots for this equation?

using the quadratic formula: [tex]x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:2\left(-4\right)}}{2\cdot \:2}[/tex]

[tex]x=\frac{5+\sqrt{33}}{2}[/tex] & [tex]\:x=\frac{5-\sqrt{33}}{2}[/tex]

janmilczek

Answer:

[tex]x_1 = \frac{5 - \sqrt{33}}{2}\\x_2 = \frac{5 + \sqrt{33}}{2}[/tex]

That's assuming we were supposed to solve for x.

Step-by-step explanation:

[tex]ax^2 + bx + c = 0\vspace{3pt}\\\Delta = b^2 - 4ac\vspace{4pt}\\x = \frac{-b \pm \sqrt{\Delta}}{2a}\\\\2x^2 - 10x - 4 = 0\\x^2 - 5x - 2 = 0\\\Delta = (-5)^2 - 4\cdot 1\cdot (-2) = 25 + 8 = 33\\x_1 = \frac{5 - \sqrt{33}}{2}\\x_2 = \frac{5 + \sqrt{33}}{2}[/tex]