Answer:
[tex]v_f=9,07~m/s[/tex]
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes uniformly in time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
[tex]v_f=v_o+at[/tex]
The car initially travels at vo=7.35 m/s and accelerates at a rate of [tex]a=0.824~m/s^2[/tex] during t=2.09 s.
The final velocity is:
[tex]v_f=7.35+0.824*2.09[/tex]
[tex]\mathbf{v_f=9,07~m/s}[/tex]
