Answer:
[tex]\mathrm{System\:of\:Equations}:\\\\\mathrm{y_1 = log(2x + 1)}\\\mathrm{y_2 = 3x - 2}[/tex]
Step-by-step explanation:
I believe you meant your question to be 'log(2x + 1) = 3x - 2.' The simplest approach to this problem would be to assign 'y' to each side of the given equation, giving us the system of equations we need.
y₁ = log(2x + 1),
y₂ = 3x - 2
By dividing the given equation into these two equations, we can equate one another so that y₁ = y₂. Therefore their intersection will be (1) the value of y₁, (2) the value of y₂, and (3) the solution to the system of equations. Hence this is your solution.
