Answer:
53.8 L
Step-by-step explanation:
We can use the ideal gas formula that relates pressure, volume and temperature:
[tex]\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}[/tex]
where P1 = initial pressure = 1.0 atm
V1 = initial volume = 45 L
T1 = initial temperature = 25°C = 25 + 273 = 298 K
P2 = final pressure = 0.78 atm
V2 = final volume
T2 = final temperature = 5.0°C = 5 + 273 = 278 K
Therefore, the final volume will be:
[tex]\frac{1 * 45}{298} = \frac{0.78 * V_2}{278}\\\\0.151 = 0.002806 V_2\\\\=> V_2 = 0.151 / 0.002806\\\\V_2 = 53.8 L[/tex]
Its volume is 53.8 L
