The Slope of the secant m = 1.
Given that, the slope of the line passing through P(2, 4) and Q ( x, f(x)) can be calculated as slope m = [tex]\frac{f(x)-4}{x+2}[/tex]
What is the slope formula?
The formula for slope (m)=rise/run=[tex]\frac{y_{2}- y_{1}}{x_{2}- x_{1}}[/tex]
⇒Slope m = [tex]\frac{-4x-x^{2} -4}{x+2}[/tex]
⇒Slope m = [tex]\frac{-(x^{2}+4x+4)}{x+2}[/tex]
⇒Slope m = [tex]\frac{-(x+2)^{2} }{(x+2)}[/tex]
⇒Slope m = -(x+2)
Passing through P(-2,4) and Q(-3,3)
Slope of the secant m = -(x+2)
Slope of the secant m = -(-3 +2)
Slope of the secant m = -( -1)
Therefore, the slope of the secant m=1.
To learn more about the slope visit:
https://brainly.com/question/3605446.
#SPJ2
