Answer:
e. it is anywhere inside (the force is zero everywhere)
Explanation:
The relation between the force and electric field is given as follows
[tex]\vec{F} = \vec{E}q[/tex]
where q is the charge inside, and E is the electric field inside the balloon created by the charge on the surface.
By Gauss' Law, the electric field inside the balloon created by the charges on the surface (excluding the charge q, since the electric field of the same charge cannot apply a force on the same charge) is zero.
[tex]\int \vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E4\pi r^2 = 0\\E = 0[/tex]
Since the external electric field inside the sphere is zero, then the force on the point charge is zero everywhere.
It is anywhere inside (the force is zero everywhere).
The electrical field on the surface of the charged sphere is calculated by applying Coulomb law;
[tex]E = \frac{Qr}{4\pi \varepsilon _0R^3}[/tex]
Electric force is calculated as follows;
F = Eq
The electric field inside the charged sphere is zero.
F = 0 x q = 0
Thus, we can conclude that, it is anywhere inside (the force is zero everywhere).
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