Answer:
45 degree from the ground
Explanation:
Range in a projectile motion is the distance traveled by the body in the horizontal distance when thrown form a point in the air.
The range of the projectile if given by,
[tex]R = \frac{u^{2} sin 2\theta }{g}[/tex]
where u = initial velocity
θ = angle of projection
g = acceleration due to gravity
Now we known that sine of 90 degree is 1 which is maximum.
Therefore,
sin 2θ = 1
sin 2(45°) = 1
sin 90° = 1
Therefore, placing the value of sin 2(45°) = 1 in the below eqyuation we get,
[tex]R_{max} = \frac{u^{2} }{g}[/tex]
Hence the answer is --- 45 degree
