Imagine that you are standing on the ground 15 feet away from a flagpole. if the top of the flag is 25 feet high, which equation represents the angle θ your feet make with the top of the flag?

Respuesta :

tan theta = 25/12, so
theta = tan^-1 (25/15)

Answer: Hence, the angle of elevation with the top of the flag is 59° and

And the equation would be [tex]\theta=\tan^{-1}(\dfrac{AB}{BC})[/tex]

Step-by-step explanation:

Since we have given that

Height of top of the flag = 25 feet

Distance of the base of flagpole from the person standing on the ground = 15 feet

We need to find the angle of elevation θ :

Consider ΔABC,

[tex]\tan \theta=\dfrac{AB}{BC}\\\\\tan\theta=\dfrac{25}{15}\\\\\tan \theta=1.67\\\\\theta=\tan^{-1}(1.67)\\\\\theta=59^\circ[/tex]

Hence, the angle of elevation with the top of the flag is 59°.

And the equation would be

[tex]\theta=\tan^{-1}(\dfrac{AB}{BC})[/tex]

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