Respuesta :
Answer:
0.00016391 V
0.00038665 V
Explanation:
r = Radius = 2 mm
[tex]B_i[/tex] = Initial magnetic field = 0
[tex]B_f[/tex] = Final magnetic field = 1.5 T
t = Time taken = 115 ms
Induced emf is given by
[tex]\varepsilon=\frac{d\phi}{dt}\\\Rightarrow \varepsilon=\frac{A(B_f-B_i)}{dt}\\\Rightarrow \varepsilon=\frac{\pi 0.002^2(1.5)}{0.115}\\\Rightarrow \varepsilon=0.00016391\ V[/tex]
The magnitude of the induced emf is 0.00016391 V
[tex]B_i=+1.5\ T[/tex]
[tex]B_f=-0.5\ T[/tex]
t = 65 ms
[tex]\varepsilon=\frac{d\phi}{dt}\\\Rightarrow \varepsilon=\frac{A(B_f-B_i)}{dt}\\\Rightarrow \varepsilon=\frac{\pi 0.002^2(-0.5-1.5)}{0.065}\\\Rightarrow \varepsilon=-0.00038665\ V[/tex]
The magnitude of the induced emf is 0.00038665 V
The production of a potential difference in a coil due to magnetic flux is known as the induced emf. The average induced emf will be 0.00016391 V.
What is a magnetic field?
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
(a) 0.00016391 V is the average induced emf around the border of the circular region.
The given data in the problem is;
r is the radius of horizontal circular region = 2.00 mm=0.002 m
[tex]\rm B_i[/tex] is the initial megnetic field=0T
[tex]\rm B_f[/tex] s the final megnetic field= 1.5 T
t is the time taken= 115 ms0.115 sec
[tex]\epsilon[/tex] is the emf induced =?
The induced emf is found by;
[tex]\epsilon = \frac{d \phi}{dt} \\\\ \epsilon = A\frac{B_f-B_i}{dt} \\\\ \epsilon = \pi r^2\frac{1.5-0}{0.115} \\\\ \epsilon = 0.00016391 \ V[/tex]
Hence 0.00016391 V is the average induced emf around the border of the circular region.
(b) 0.00038665 V is the average induced emf around the border of the circular region over this time period.
The given data in the problem is;
r is the radius of horizontal circular region = 2.00 mm,
[tex]\rm B_i[/tex] is the initial megnetic field=+1.5 T
[tex]\rm B_f[/tex] s the final megnetic field= -1.5 T
t is the time taken= 65 ms=0.065 sec
[tex]\epsilon[/tex] is the emf induced =?
[tex]\epsilon = \frac{d \phi}{dt} \\\\ \epsilon = A\frac{B_f-B_i}{dt} \\\\ \epsilon = \pi (0.002)^2\frac{-0.5-1.5}{0.065} \\\\ \epsilon = -0.00038665 \ V[/tex]
Hence 0.00038665 V is the average induced emf around the border of the circular region over this time period.
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022