Answer:
19.2 kg/person/year
Step-by-step explanation:
[tex]\dfrac{5.77\cdot 10^6\,T}{1\,US\cdot year}\cdot\dfrac{1000\,kg}{1\,T}\cdot\dfrac{1\,US}{3.01\cdot 10^8\,persons}=\dfrac{5.77\cdot 10^6\cdot 1000\,kg}{3.01\cdot 10^8\,person\cdot year}\\\\\approx 19.2\,\text{kg/person/year}[/tex]