A block wełghing 300 N is moved at a constant speed over a horizontal
surface by a force of 50 N. What is the coefficient of friction? *
1 point
A. 0.25
OB. 0.50
C. 0.10
D. 0.17

Respuesta :

Answer:

D) miu = 0.17

Explanation:

To be able to solve this problem we must perform a sum of forces in the direction of the movement. This sum of forces must be equal to zero, since the block moves at a constant speed, therefore there is no acceleration.

The friction force is defined as the product of the normal force by the coefficient of friction.

[tex]f=miu*N[/tex]

where:

f = friction force = 50 [N]

miu = friction coefficient

N = normal force [N]

Now the normal force is defined as the force with equal magnitude to the weight of the block but acting in the opposite direction.

[tex]N=300[N][/tex]

Now replacing:

[tex]miu=f/N\\miu=50/300\\miu = 0.166\\ or 0.17[/tex]