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A person walks first at a constant speed of 5.50 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3. What is her average speed over the entire trip (in m/s) ?

Respuesta :

MathPhys

Answer:

4.25 m/s

Explanation:

They walked the first distance at 5.50 m/s, then the same distance at 3 m/s.

Since the distances are equal, the average speed is simply the average of 5.50 and 3.

(5.50 + 3) / 2 = 4.25

Her average speed over the entire trip is 4.25 m/s.

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