Eduardo has a red 6-sided number cube and a blue 6-sided number cube. The faces of the cubes are numbered 1 through 6. Eduardo rolls both cubes at the same time. The random variable X is the number on the red cube minus the number on the blue cube. What is P(−2≤X≤1)? Enter your answer, in simplest fraction form, in the box.

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ashbyhailey ashbyhailey · Answer 1 · 2019-04-09T20:21:54+02:00

Answer: 5/9

Step-by-step explanation: Just took the test

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ikarus ikarus · Answer 2 · 2019-05-15T20:32:08+02:00

Answer:

P(−2≤X≤1) = 5/9.

Step-by-step explanation:

Given:

P(-2≤X≤1) and he random variable X is the number on the red cube minus the number on the blue cube

x = -2. -1. 0 and 1

Let's take first number as in the red cube and the second number is in blue cube.

We get x = -2 for the following outcomes

(1, 3), (2, 4), (3, 5), and (4, 6). which is 4 favorable outcomes.

We get x = -1, for the following outcomes:

(1, 2), (2, 3), (3, 4), (4, 5), and (5, 6). which is 5 favorable outcomes

We get x = 0, when (1, 1) (2, 2)(3, 3)(4, 4) (5, 5),(6, 6) which is 6

We get x = 1, when (2, 1), (3, 2) (4, 3) (5, 4) (6, 5), which is 5.

The number of favorable outcomes= 4 + 5 + 6 + 5 = 20

The number of possible outcomes = 36 (when we toss the two dices, the possible number of outcomes is 36)

The required probability P(−2≤X≤1) = The total number of favorable outcomes / the total number of possible outcomes

= 20/36

P(−2≤X≤1) = 5/9.

Hope this will helpful.

Thank you.