Answer:
After the sale there were 15 cars and 5 motorcycles
Step-by-step explanation:
c=cars originally
m=motorcycles originally
c=2m (2 times the cars than motorcycles)
(c+1) bought 1 car after sale
sold 1 motor cycle (m-2) after sale
(c+1) = 3(m-2) (3 times more cars than motorcycles)
(c+1) = 3(m-2)
distribute
c+1 = 3m-6
substitute c =2m
2m +1 = 3m-6
subtract 2m from each side
2m+1-2m = 3m-6-2m
1 = m-6
add 6 to each side
1+6 = m-6+6
m=7
c = 2m
c = 2(7) =14
c=14
Originally there were 7 motorcycles and 14 cars
After the sale c+1 = 15, m-2 = 5
there were 15 cars and 5 motorcycles
Answer:
In the Garage, Numeber of cars are 15 and Number of motorcycles are 5
Step-by-step explanation:
let number of motorcycles be = x
he had 2 times more cars than motorcycles so ,no of cars = 2x
he bought 1 more car,so number of cars = 2x+1
he sold 2 motorcycles,so motorcycles = x-2
he had 3 times more cars than motorcycles so, we equate it like this:
3(x-2) = 2x+1
solving the equation
3x-6 = 2x+1
here we find , x=7
solving for no of cars:
2x+1
2(7)+1
no of cars = 15
solving for no of motorcycles:
x-2
7-2
no of motorcycles = 5
