Respuesta :
Answer:
The time is 8.8 hr.
Explanation:
Given that,
Final velocity = 44 km/hr
Acceleration = 5 km/hr²
We need to calculate the time
Using equation of motion
[tex]v= u+at[/tex]
Where, v = final velocity
u = initial velocity
a = acceleration
Put the value into the formula
[tex]44=0+5\times t[/tex]
[tex]t = \dfrac{44}{5}[/tex]
[tex]t =8.8\ hr[/tex]
Hence, The time taken is 8.8 hr.
The time of motion of the car is 8.8 hours.
The given parameters;
acceleration of the car, a = 5 km/hr²
the velocity of the car, v = 44 km/hr
Acceleration is defined as the change in velocity per change in time. Also acceleration of an object increase as the velocity increases. At an equal rate of change of velocity, the acceleration will be constant. If the change in velocity with is zero, the acceleration of the object will be zero.
The time of motion of the car is calculated from the following equation;
[tex]a = \frac{\Delta \ Velocity }{\Delta \ time} \\\\time = \frac{Velocity}{acceleration} = \frac{44}{5} = 8.8 \ hr[/tex]
Thus, the time of motion of the car is 8.8 hours.
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