Respuesta :

kenmyna
The number  of grams  of oxygen  present  in  1.75  moles  of  calcium   carbonate    is  84  grams

    Explanation

mass  =  moles x molar mass
molar  mass  =  16 g/mol

find the  number  of moles of  oxygen  in calcium  carbonate as below
formula  of    calcium  carbonate  is CaCO3

 from the  formula above    have   three(3)  atoms  of  oxygen


therefore  the moles  of  0xygen =  3 x 1.75 =5.25  moles

mass of  oxygen  is therefore = 5.25  moles  x16g/mol  =  84 grams  of  oxygen

The number of grams of oxygen present in 1.75 moles of calcium carbonate is 84 grams.

How we calculate weight from moles?

Required mass of any substance from moles will be calculated as:

n = W/M, where

W = required mass?

M = molar mass

Given moles of calcium carbonate (CaCo₃) = 1.75

From the stoichiometry of the given compound it is clear that:

1 mole of CaCo₃ = will contain 3 moles of oxygen

1.75 moles of CaCo₃ = will contain 3×1.75=5.25 moles of oxygen

Mass of oxygen = 5.25 × 16 = 84 grams.

Hence, 84 grams of oxygen is present.

To know more about moles, visit the below link:

https://brainly.com/question/1034638

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