Respuesta :
(a) we multiply the individual probabilities ( because they are independent):-
answer = 0.95626^2 = 0.91443
(b) this is 0.95626^7 = 0.73119
(c) Prob(at least one does not live until 4 years old) = 1 - Prob( all seven will live until 4 years old) = 1 - 0.73119 = 0.2688.
it would not be unusual for the last probability to happen - its a chance of about 1 in 4.
The respective probabilities of each of the given problems are;
a) 0.9144
b) 0.7312
c) 0.2688
What is the probability?
a) We are given;
Probability that a randomly selected 3-year-old male feral cat will live to be 4 years old = 0.95626
We want to find the probability that two randomly selected 3-year-old male feral cats will live to be 4 years old. This means both probabilities are indpendent and so;
P(two will live to be 4 years old) = 0.95626 * 0.95626 = 0.9144
(b) We want to find the probability that seven randomly selected 3-year-old male feral cats will live to be 4 years old. This is;
P(7 randomly selected will live) = 0.95626⁷ = 0.7312
(c) P(at least one does not live until 4 years old) = 1 - P(7 randomly selected)
P(at least one does not live until 4 years old) = 1 - 0.7312 = 0.2688.
Thus, it is not unusual for this probability to happen since it represents approximately more than a 1 to 4 chance.
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