we are given
[tex] a=ln(2) [/tex]
[tex] b=ln(3) [/tex]
(39)
[tex] ln(6) [/tex]
we can write it as
[tex] ln(6)=ln(2*3) [/tex]
now, we can use property of log
[tex] ln(6)=ln(2)+ln(3) [/tex]
now, we can replace with a and b
and we get
[tex] ln(6)=a+b [/tex]............Answer
(43)
[tex] ln(9) [/tex]
we can write it as
[tex] ln(9)=ln(3^2) [/tex]
now, we can use property of log
[tex] ln(9)=2ln(3) [/tex]
now, we can replace with a and b
and we get
[tex] ln(9)=2b [/tex]............Answer