A hose with a larger diameter working alone can fill a swimming pool in 9 hours. A hose with a smaller diameter working alone can fill a swimming pool in 18 hours. Working together, how long would it take the two hoses to fill the swimming pool?

Respuesta :

- The rate of the hose with the large diameter is:

  Answer: A). 1/9.

- What is the unknown in the problem?

  Answer: C). the time it takes for the hoses working together to fill the pool

-What part of the job does the hose with the large diameter do?

  Answer: B). x/9

Using the together rate, it is found that working together, it would take 6 hours for the two hoses to fill the swimming pool.

What is the together rate?

  • The together rate is the sum of each separate rate.

In this problem, the rates are as follows:

  • The together rate is of [tex]\frac{1}{x}[/tex].
  • For the hose with the larger diameter, the rate is of [tex]\frac{1}{9}[/tex].
  • For the hose with the smaller diameter, the rate is of [tex]\frac{1}{18}[/tex].

Then, the together rate is of:

[tex]\frac{1}{x} = \frac{1}{9} + \frac{1}{18}[/tex]

[tex]\frac{1}{x} = \frac{2 + 1}{18}[/tex]

[tex]3x = 18[/tex]

[tex]x = \frac{18}{3}[/tex]

[tex]x = 6[/tex]

It would take 6 hours for the two hoses to fill the swimming pool.

To learn more about the together rate, you can take a look at https://brainly.com/question/25159431