Answer: A) 1245.71 meters
Step-by-step explanation:
Given: The line of best fit, in blue, has equation [tex]C = 23.72 - 0.007m[/tex]
When we put the mean temperature=15° C, we get
[tex]15= 23.72-0.007m\\\\\Rightarrow-0.007m=15-23.72\\\\\Rightarrow-0.007m=-8.72\\\\\Rightarrow m=\frac{-8.72}{-0.007}=1245.71428571\approx1245.71\ meters[/tex]
Hence, the linear model predict a mean temperature of 15° C for 1245.71 meters of elevation.