Respuesta :
ΔABO is a right triangle with AB⊥BO. The radius of the circle is BO. The Pythagorean theorem applies.
AO² = AB² + BO²
13² = 5² + r²
169 -25 = r²
r = √144 = 12
The radius (r) is 12.
AO² = AB² + BO²
13² = 5² + r²
169 -25 = r²
r = √144 = 12
The radius (r) is 12.