Respuesta :

transitionstate
When CH₄ is burnt in excess O₂ following products are formed,

                           CH₄  +  2 O₂     →     CO₂  +  2 H₂O

According to equation 1 mole of CH₄ (16 g) reacts with 2 moles of O₂ to produce 1 mole of CO₂ and 2 moles of H₂O. Hence the products are,

                          1 mole of CO₂  and  2 moles of H₂O

Converting 1 mole CO₂ to grams;
As,
                           Mass  =  Moles × M.mass

                           Mass  =  1 mol ×  44 g.mol⁻¹

                           Mass  =  40 g of CO₂

Converting 2 moles of H₂O to grams,

                           Mass  =  2 mol ×  18 g.mol⁻¹
                         
                           Mass  =  36 g of H₂O

Total grams of products;

                           Mass of CO₂  =  44 g
                    +     Mass of H₂O  =  36 g
                                                  -------------
                           Total              =   80 g of Product

Result:
            80 grams of product is formed when 16 grams of CH₄ is burnt in excess of Oxygen.
mahima6824soni

The total mass of product formed is 80 grams.

What is mass?

Mass is the quantity of matter of a physical body.

The reaction is

[tex]\rm CH_4 + 2 O_2 = CO_2 + 2 H_2O[/tex]

When methane is burned in excess of oxygen, carbon dioxide and water is formed.

Now, by the reaction

There are one mole of CO₂ and 2 moles of H₂O

Converting the mole into gram

For carbon dioxide

mass = moles × mass

1 mol × 44 g.mol = 40 g of CO₂

For water

2 mol ×  18 g.mol  =  36 g of H₂O

Now, add the total grams

40 + 36 = 80 g

Thus, 80 grams of product is formed when 16 grams of CH₄ is burnt in excess of oxygen.

Learn more about mass, here:

https://brainly.com/question/19694949