The two lines, P and Q, are graphed below: Line P is drawn by joining ordered pairs negative 8,15 and 6, negative 12. Line Q is drawn by joining ordered pairs 4,16 and negative 9,10 Determine the solution and the reasoning that justifies the solution to the systems of equations

Respuesta :

Answer:

[tex]\text{Solution: }\left(-\dfrac{2654}{435},\dfrac{1644}{145}\right)[/tex]

Step-by-step explanation:

Line P is drawn by joining ordered pairs (-8,15) and (6,-12)

Using two point formula of line. Find equation of line P

[tex]\dfrac{y-15}{x-(-8)}=\dfrac{-12-15}{6-(-8)}[/tex]

[tex]\dfrac{y-15}{x+8}=\dfrac{-27}{6+8)}[/tex]

[tex]\dfrac{y-15}{x+8}=\dfrac{-27}{14}[/tex]

[tex]y=\dfrac{-27}{14}(x+8)+15[/tex]

[tex]y=\dfrac{-27}{14}x+\dfrac{-27}{14}\times 8 + 15[/tex]

[tex]y=\dfrac{-27}{14}x-\dfrac{3}{7}[/tex]

[tex]\text{Equation of line P:}y=\dfrac{-27}{14}x-\dfrac{3}{7}[/tex]

Line Q is drawn by joining ordered pairs (4,16) and (-9,10)

Using two point formula of line. Find equation of line Q

[tex]\dfrac{y-16}{x-4}=\dfrac{10-16}{-9-4}[/tex]

[tex]\dfrac{y-16}{x-4}=\dfrac{-6}{-13}[/tex]

[tex]\dfrac{y-16}{x-4}=\dfrac{6}{13}[/tex]

[tex]y=\dfrac{6}{13}(x-4)+16[/tex]

[tex]y=\dfrac{6}{13}x-\dfrac{6}{13}\times 4 + 16[/tex]

[tex]y=\dfrac{6}{13}x+\dfrac{184}{13}[/tex]

[tex]\text{Equation of line Q:}y=\dfrac{6}{13}x+\dfrac{184}{13}[/tex]

Using graphing find solution of system of equation.

We draw the line on graph and see the intersection point.

Please see the attachment of the line.


Ver imagen isyllus

Answer:

(−2, 4), because it is the point of intersection of the two graphs

Step-by-step explanation:

BECAUSE