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Which set of ordered pairs could be generated by an exponential function?
(0, 0), (1, 1), (2, 8), (3, 27)
(0, 1), (1, 2), (2, 5), (3, 10)
(0, 0), (1, 3), (2, 6), (3, 9)
(0, 1), (1, 3), (2, 9), (3, 27)

Respuesta :

carlosego

For this case we must find the set of ordered pairs that form an exponential function.

When observing, the last set of ordered pairs is an exponential function of the form:

[tex]y = 3 ^ x[/tex]

For x = 0:

[tex]y = 3 ^ 0 = 1[/tex]

We have the ordered pair:

[tex](x, y): (0, 1)[/tex]

For x = 1:

[tex]y = 3 ^ 1 = 3[/tex]

We have the ordered pair:

[tex](x, y): (1, 3)[/tex]

For x = 2:

[tex]y = 3 ^ 2 = 9[/tex]

We have the ordered pair:

[tex](x, y): (2, 9)[/tex]

For x = 3:

[tex]y = 3 ^ 3 = 27[/tex]

We have the ordered pair:

[tex](x, y): (3, 27)[/tex]

Answer:

The set of ordered pairs that form an exponential function is:

[tex](0, 1), (1, 3), (2, 9), (3, 27)[/tex]

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