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dexteright02
Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100 g solution)

C: 83.7% = 83,7 g 
H: 16.3% = 16.3 g 

Let us use the above mentioned data (in g) and values will be ​​converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

[tex]C: \dfrac{83.7\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 6.975\:mol[/tex]

[tex]H: \dfrac{16.3\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 16.3\:mol[/tex]

We note that the values ​​found above are not integers, so let's divide these values ​​by the smallest of them, so that the proportion is not changed, let's see:

[tex]C: \dfrac{6.975}{6.975} = 1[/tex]

[tex]H: \dfrac{16.3}{6.975} \approx 2.3[/tex]

Note: So the ratio in the smallest whole numbers of carbon to hydrogen is 3:7, thus, the minimum or empirical formula found for the compound will be:

[tex]\boxed{\boxed{C_3H_7}}\end{array}}\qquad\checkmark[/tex]

I hope this helps. =)

The empirical formula should be [tex]C_3H_7[/tex]

  • The calculation is as follows:

C: 83.7% = 83,7 g

H: 16.3% = 16.3 g

Now

[tex]C = 83.7 \div 12 = 6.975 mol\\\\H = 16.3 \div 1 = 16.3 mol[/tex]

The above does not represent the integers

So,

[tex]C = 6.975 \div 6.975 = 1\\\\H = 16.3 \div 6.975 = 2.3[/tex]

Therefore the above empirical formula should be used.

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