Respuesta :

carlosego
For this case we have the following expression:
 5x3 + 40y6
 Common factor 5:
 5 (x3 + 8y6)
 Factoring the expression within the parenthesis we have:
 5 ((x + 2y2) (x2 - 2xy2 + 4y4))
 Answer:
 The factored expression is given by:
 5 ((x + 2y2) (x2 - 2xy2 + 4y4))

Answer: The expression after completely factorised form is

[tex]5[(x+2y^2)(x^2+4y^4-2xy^2)][/tex]

Step-by-step explanation:

Since we have given that

[tex]5x^3 + 40y^6[/tex]

We need to factorise it completely:

[tex]5x^3 + 40y^6\\\\=5(x^3+8y^6)\\\\=5((x)^3+(2y^2)^3)\\\\=5[(x+2y^2)(x^2+4y^4-2xy^2)]\ (\because\ a^3+b^3=(a+b)(a^2+b^2-ab))[/tex]

Hence, the expression after completely factorised form is

[tex]5[(x+2y^2)(x^2+4y^4-2xy^2)][/tex]

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