Respuesta :
The quadratic formula is:
[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]
b =coefficient of x term = 24
a = coefficient of squared term = 9
c = constant term = 32
Using the values, we get:
[tex]x= \frac{-24+- \sqrt{576-4(9)(32)} }{2(9)} \\ \\ x= \frac{-24+- \sqrt{-576} }{18} \\ \\ x= \frac{-24+-24i}{18} \\ \\ x= \frac{-4+-4i}{3} \\ \\ x= \frac{-4+4i}{3}, x \frac{-4-4i}{2} [/tex]
[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]
b =coefficient of x term = 24
a = coefficient of squared term = 9
c = constant term = 32
Using the values, we get:
[tex]x= \frac{-24+- \sqrt{576-4(9)(32)} }{2(9)} \\ \\ x= \frac{-24+- \sqrt{-576} }{18} \\ \\ x= \frac{-24+-24i}{18} \\ \\ x= \frac{-4+-4i}{3} \\ \\ x= \frac{-4+4i}{3}, x \frac{-4-4i}{2} [/tex]
The first step for solving this equation is to multiply the first two numbers together.
18 + 24x + 32 = 0
Add together 18 and 32.
50 + 24x = 0
Now move the constant to the right side of the equation and change its sign.
24x = -50
Lastly,, divide both sides of the equation by 24.
x = [tex]- \frac{25}{12} [/tex]
This means that the correct answer to your question is going to be x = [tex]- \frac{25}{12} [/tex] or x = [tex]-2 \frac{1}{12} [/tex] simplified.
Let me know if you have any further questions.
:)
18 + 24x + 32 = 0
Add together 18 and 32.
50 + 24x = 0
Now move the constant to the right side of the equation and change its sign.
24x = -50
Lastly,, divide both sides of the equation by 24.
x = [tex]- \frac{25}{12} [/tex]
This means that the correct answer to your question is going to be x = [tex]- \frac{25}{12} [/tex] or x = [tex]-2 \frac{1}{12} [/tex] simplified.
Let me know if you have any further questions.
:)
