faber8e
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Write in slope-intercept form an equation of the line that passes through the given points.

(−1, −1), (1, 5)

Respuesta :

kanest
Slope-intercept form uses the following equation: y = mx + b. m is the slope, and b is the y-intercept of the equation.

Use the following formula to figure out the rise and run of these points:

[tex] \frac{y2 - y1}{x2 - x1} [/tex]

Plug the x and y values into the equation to determine the slope.

[tex] \frac{5 - (-1)}{1 - (-1)} [/tex] = [tex] \frac{6}{2} [/tex] = 3

Use the slope to find the y-intercept of the equation. You can find this by taking a point and using addition/subtraction and multiplication.

Taking the point (1,5), you can do the following:

5 - 3(1) = 2

The final equation is y = 3x + 2.

CharlieBrown2002

Answer: y=3x+2

Explanation:

Slope-intercept form: → [tex]y=mx+b[/tex]

m: represents the slope and is constant.

b: represents the y-intercept.

The y-intercept is the point on a graph at which the graph crosses the y-axis.

Used rise/run.

[tex]m=\frac{rise}{run}[/tex]

[tex]rise=y^2-y^1[/tex]

[tex]run=x^2-x^1[/tex]

[tex](x^1,y^1)=(-1,-1)[/tex]

[tex](x^2,y^2)=(1,5)[/tex]

[tex]rise=y^2-y^1=5-(-1)[/tex]

[tex]run=x^2-x^1=1-(-1)[/tex]

[tex]\frac{5-(-1)}{1-(-1)}= \frac{6}{2}=3*2=6=3[/tex]

[tex]5-3(1)=2(1)=2*1=2[/tex]

Hope this helps!

Thanks!

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