Respuesta :
For this case we have the following equation:
h (t) = - 12t2 + 36t
When the object hits the ground we have:
- 12t2 + 36t = 0
We look for the roots of the polynomial:
t1 = 0
t2 = 3
Therefore, the time it takes the object to hit the ground is:
t = 3 s
Answer:
the time when the object hits the ground is:
t = 3 s
h (t) = - 12t2 + 36t
When the object hits the ground we have:
- 12t2 + 36t = 0
We look for the roots of the polynomial:
t1 = 0
t2 = 3
Therefore, the time it takes the object to hit the ground is:
t = 3 s
Answer:
the time when the object hits the ground is:
t = 3 s
Answer:
3 seconds is the time when the object hits the ground.
Step-by-step explanation:
Given the height of a free falling object at time t can be found using the function is given by:
[tex]h(t)=-12t^2+36t[/tex] ....[1]
where,
h(t) is the height in feet
t is the in seconds.
We have to find the time when the object hits the ground.
⇒h(t) = 0
Substitute this in [1] we have;
[tex]-12t^2+36t =0[/tex]
⇒[tex]12t^2-36t = 0[/tex]
⇒[tex]12t(t-3) = 0[/tex]
⇒t = 0 and t = 3
Since, time cannot be 0.
⇒t = 3 seconds
Therefore, the time when the object hits the ground is, 3 seconds