If the racetrack publishes that the odds in favor of a horse winning a race are 5 to 9, what is probability that the horse will not win the race?

I divided 5 by 9 and multiplied it by 100 to get the percentage for the probability the horse will win. I got 55.55%. I subtracted 55.55 from 100 and got 44.45% chance of not winning the race.

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JeanaShupp JeanaShupp · Answer 2 · 2019-12-20T04:06:44+01:00

Answer: [tex]\dfrac{9}{14}[/tex]

Step-by-step explanation:

We know that , In probability the odds for an event is the ratio of the favorable outcomes to the unfavorable outcomes.

We are given that ,

The racetrack publishes that the odds in favor of a horse winning a race are 5 to 9 .

i.e. favorable outcomes for horse winning a race = 5

i.e. unfavorable outcomes for horse winning a race = 9

Now , Total outcomes = favorable outcomes+ unfavorable outcomes

= 5+9 = 14

Then, the probability that the horse will not win the race[tex]=\dfrac{\text{Unfavorable outcomes}}{\text{Total outcomes}}[/tex]

[tex]=\dfrac{9}{14}[/tex]

Hence, the probability that the horse will not win the race =[tex]\dfrac{9}{14}[/tex]