we know that [volume of the cone]=(1/3)*area of the base*height h-----> height AB-----> area of the base so [volume of the original cone]=(1/3)*AB*h volume=6 in³ (1/3)*AB*h=6--------> h=18/AB
For a cone with the same base diameter but a volume of only 3 cubic inches (1/3)*AB*h=3 in³-------> h=9*AB
the answer is The new cone height is half the original height
