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Darren is finding the equation in the form y=mx+b for a trend line that passes through the points (2, 18) and (–3, 8). Which value should he use as b in his equation?

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fatehahnordin9p7wo43
gradient = (8-18)/(-3-2)
= -10/-5
= 2

y = mx + b , at point ( -3,8 )
8 = 2(-3) + b
8 = - 6 + b
b = 14

we cannot simply take one of the y coordinate as value of b because b is the interception of straight line,not a point
Hello!

B - Y-intercept

First, let's write out the equation by finding the slope

[tex]y = mx + b [/tex]

[tex] \frac{8-18}{-3-2} = \frac{-10}{-5} = 2[/tex]

Our slope is 2. Let's plug this in

[tex]y = 2x + b[/tex]

Now let's find the y-intercept. Plug one of the x and y values into the equation. I'll use the ones for (2, 18) since they're positive.

[tex]18 = 2(2) + b 18 = 4 + b 18 - 4 = 4 - 4 + b 14 = b [/tex]

He should use the number 14 as the y-intercept. Here's what his equation will look like.

[tex]y = 2x + 14[/tex]

Hope I helped! :3




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