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each of the circles below has an area of 196 pi square units find the perimeter of the rectangle

each of the circles below has an area of 196 pi square units find the perimeter of the rectangle class=

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Answer:

Step-by-step explanation:

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We have given the area of each circle as 196 pi square units.

since the area of the circle =[tex]\pi*radius^2[/tex]

so,the radius of the circle :

[tex]196\pi =\pi r^2[/tex]

[tex]r^2=196[/tex]

[tex]r=14[/tex]

therefore the diameter of the circle will be [tex]2*radius=2*14=28[/tex]

the perimeter of the rectangle=[tex]2*(length+ width)[/tex]

the length of the rectangle will be addition of diameters of the circle=[tex]28+28=56[/tex]

breadth of the rectangle is equal of the diameter =28

Perimeter of the rectangle =[tex]2*(56+28)=168[/tex]

Answer  168 units.

The perimeter of the given rectangle is 168 units

Given that area of each of the circles are [tex] 196 \pi [/tex] sq units and we know that the area of circle [tex]=\pi r^{2}[/tex] using this radius of the circle will be

[tex]\pi r^{2} =196\pi\\ r^{2} = 196\\ \\ r=14[/tex]

So, the diameter of the circle is twice the radius which is

[tex]2\times r\\ 2\times 14 =28 [/tex]

Here we can see that length of rectangle is equal to twice the diameter of the circle and breadth is equals to twice the radius

[tex]length= 28+28=56[/tex]

[tex]breadth = 2\cdot14=28[/tex]

How to find the perimeter of the given rectangle ?

To find the perimeter we use the formula

Perimeter of rectangle = [tex]2\cdot(length + breadth)[/tex]

On solving we get ,

[tex]2\cdot(56 +28)\\ 168 units[/tex]

Therefore, The perimeter of the given rectangle is 168 units

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